Shepherd of the Valley to Host Job Fair Sept. 30

YOUNGSTOWN, Ohio — Shepherd of the Valley will host a job fair from 9 a.m. to 3 p.m. Sept. 30 at its offices on Silica Road in Austintown. The purpose is to recruit staff for all five Shepherd centers locations and its home health agency.

Shepherd management will conduct interviews for all available positions and is prepared to hire onsite. The positions can be viewed here http://www.shepherdofthevalley.com

Applicants should bring photo identification. Those interested in a position that requires travel should also bring proof of auto insurance.

For more information, call Celina Williams, human resources director, at 330 530 4038, extension 2038.

Pictured: Shepherd of the Valley Boardman.

Copyright 2022 The Business Journal, Youngstown, Ohio.